Queen Of Enko Fix -

def solve_n_queens(n): def can_place(board, row, col): for i in range(col): if board[row][i] == 1: return False

return True

for i in range(n): if can_place(board, i, col): board[i][col] = 1 place_queens(board, col + 1) board[i][col] = 0 queen of enko fix

The solution to the Queen of Enko Fix can be implemented using a variety of programming languages. Here is an example implementation in Python: def solve_n_queens(n): def can_place(board, row, col): for i

# Test the function n = 4 solutions = solve_n_queens(n) for i, solution in enumerate(solutions): print(f"Solution {i+1}:") for row in solution: print(row) print() def solve_n_queens(n): def can_place(board

def place_queens(board, col): if col >= n: result.append(board[:]) return

for i, j in zip(range(row, n, 1), range(col, -1, -1)): if board[i][j] == 1: return False