T(x,t) = 100 - 80 * erf(x / 0.2) + 4 * (1 - (x/0.02)^2)
Substituting the given values, the temperature distribution in the wall at t = 10 s can be determined as: incropera principles of heat and mass transfer solution pdf
α = k / (ρ * c_p)
T(x,t) = 100 + (20 - 100) * erf(x / (2 * √(0.01 * 10))) + (1000 * 0.02^2 / 10) * (1 - (x/0.02)^2) T(x,t) = 100 - 80 * erf(x / 0
The solution to this problem involves using the one-dimensional heat conduction equation, which is given by: incropera principles of heat and mass transfer solution pdf
The resulting temperature distribution is: